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s7b
Oct10-11, 05:36 PM
Its been a while since I took calculus so I'm confused as how to solve this.

I've gotten my equation simplified as far as

BdT=KdP and I'm supposed to solve for dP

I do it and end up with B(T2-T1) = K(P2-P1)
but this is giving me the wrong answer when I put the values in...

What am I doing wrong?

Fayez
Oct10-11, 06:13 PM
\int B dT = \int k \text{dP} \rightarrow BT + C_1 = kP + C_2
combine C= C_1 -C_2
\frac{BT + C}{k} = P

s7b
Oct10-11, 06:29 PM
How are you supposed to solve something like that not knowing what C is though?

Fayez
Oct10-11, 07:31 PM
P is a function of T
P(T)
suppose you have a value of P(0) then to solve for C
T=0
P(0) = \frac{C}{k}

therefore,
P(T) = \frac{B}{k} T + P(0) = \frac{B}{k} T + \frac{C}{k}