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Mo
Nov25-04, 05:09 PM
Im feeling stupid today.


{\sqrt{3}x = x + {\sqrt{3}}


The x is not (square rooted)

Can somebody please throw me in the right direction ??

Integral
Nov25-04, 05:17 PM
Collect your x terms to one side, factor out the x. You should be able to take it from there.

mborn
Nov25-04, 05:22 PM
\sqrt{3} x - x = \sqrt {3}
then take x as a common factor

M B

mborn
Nov25-04, 05:23 PM
why didn't my [tex] appear?

M B

Mo
Nov25-04, 05:25 PM
Thanks both.Got the answer, checked it and its correct :)

Regards,
Mo

Mo
Nov25-04, 05:26 PM
You put "[tex]" to end the statement.It should be [ / tex] :smile:

mborn
Nov25-04, 05:30 PM
Thanks!

M B