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Mo
Nov28-04, 02:18 PM
Indices.Again i think i've got close to the answer, it just does not want to show its self! A push in the right direction would be appreciated ... heres the problem:

2x^ \frac{1} {4} = \frac{64} {x}

Regards
Mo

Muzza
Nov28-04, 02:27 PM
Multiply both sides by x. Remember that x = x^1 and x^a * x^b = x^(a + b) for all a, b.

Mo
Nov28-04, 02:44 PM
Hmm i multiplied both sides by x ..i think the answer is:

2x^ \frac{2} {4} = 64 right?? ... carrying on ...

then divide both sides by 2 ..so we are left with ..

x ^\frac {2} {4} = 32

am i along the right lines here??

Hurkyl
Nov28-04, 02:46 PM
How did you get x^{2/4}?

Mo
Nov28-04, 02:51 PM
hmm, i multiple both sides by x so

2x^ \frac {1} {4} X x = 2x^ \frac {1} {4} X x^1

and since we add the indices when multiplying i get 2 no?

Mo
Nov28-04, 02:52 PM
oh lol i think i just spotted it ..

Mo
Nov28-04, 02:55 PM
edit: should be 1.25 right?

Ack - stupid mistakes , i got it now.Completely overlooked it .. :blushing: .

Thanks both :smile: