Question about integrals in general

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The integral of csc(x) from -π to 0 cannot be evaluated directly due to the function being undefined at x=0 and x=-π. However, using the Cauchy principal value technique allows for evaluation by splitting the integral into two parts: from -π to -ε and from -ε to 0, where ε approaches 0. This method enables the integral to be computed despite the discontinuities at the endpoints.

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Ed Quanta
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Let's say I have an integral from -pi to 0 of csc(x)dx

This obviously is equal to ln|csc0 - cot0| - ln|csc(-pi) - cot(-pi)|

But csc is undefined for both these values., so is this integral not able to be evaluated? Or can we just let csc0 and csc(-pi) be equal to 0? Oh so confused. Please help.
 
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Ed Quanta said:
Let's say I have an integral from -pi to 0 of csc(x)dx

This obviously is equal to ln|csc0 - cot0| - ln|csc(-pi) - cot(-pi)|

But csc is undefined for both these values., so is this integral not able to be evaluated? Or can we just let csc0 and csc(-pi) be equal to 0? Oh so confused. Please help.

Evaluate the defined integral wrt to the limits "a" and "b" and then,in the final result,which should be a function of "a" and "b" let the limits a->-pi and b->O.

Good luck!
 



Great question! When dealing with integrals, it is important to remember that the function being integrated must be continuous over the entire interval of integration. In this case, the function csc(x) is indeed undefined at x=0 and x=-pi. However, we can still evaluate the integral by using a technique called the Cauchy principal value.

The Cauchy principal value allows us to handle integrals where the function being integrated is undefined at certain points. In this case, we can rewrite the integral as the sum of two integrals: from -pi to -epsilon and from -epsilon to 0, where epsilon is a very small positive number. Then, we can take the limit as epsilon approaches 0 to find the integral from -pi to 0.

So, to answer your question, yes, we can let csc0 and csc(-pi) be equal to 0 in this case and use the Cauchy principal value to evaluate the integral. I hope this helps clarify things for you!
 

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