View Full Version : rough root equation, need help
vabamyyr
Dec1-04, 01:17 PM
\sqrt{x} + \sqrt{x+2} + \sqrt{x}\sqrt{x+2}=16,5-x
Is \sqrt{x}x=x^{\frac{3}{2}} ?
Or is this a typo?
Hint:
\frac{1}{2}(\sqrt{x}+\sqrt{x+2})^{2}=x+\sqrt{x}\sq rt{x+2}+1
vabamyyr
Dec1-04, 02:10 PM
Hint:
\frac{1}{2}(\sqrt{x}+\sqrt{x+2})^{2}=x+\sqrt{x}\sq rt{x+2}+1
thanks, i knew i had to transform my initial equation to square equation over new variable, so, yes, ur hint is the key, thanks again
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.