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vabamyyr
Dec1-04, 01:17 PM
\sqrt{x} + \sqrt{x+2} + \sqrt{x}\sqrt{x+2}=16,5-x

arildno
Dec1-04, 01:36 PM
Is \sqrt{x}x=x^{\frac{3}{2}} ?
Or is this a typo?

arildno
Dec1-04, 01:48 PM
Hint:
\frac{1}{2}(\sqrt{x}+\sqrt{x+2})^{2}=x+\sqrt{x}\sq rt{x+2}+1

vabamyyr
Dec1-04, 02:10 PM
Hint:
\frac{1}{2}(\sqrt{x}+\sqrt{x+2})^{2}=x+\sqrt{x}\sq rt{x+2}+1

thanks, i knew i had to transform my initial equation to square equation over new variable, so, yes, ur hint is the key, thanks again