How fast was the ball moving when it left the pool table?

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The discussion focuses on calculating the initial velocity of a pool ball that falls from a height of 95 cm and hits the ground at a speed of 6.0 m/s. The user employs the conservation of mechanical energy theorem, applying the formula \(\frac{1}{2} (0.85)v^2 + (0.85)g(0.95) = \frac{1}{2} (0.85)(6)^2\). The calculations lead to an initial velocity of approximately 4.17 m/s. The user expresses uncertainty about the application of the formula but intends to use it for solving the problem.

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HELP! PlEaSe

Okay, here is my problem: In a wild shot, Bo knocks a pool ball of mass of .85 kilograms offa 95-cm high pool table, and the ball hits the floor with a speed of 6.0 m/s. How fast was the ball moving when it left the pool table?
I don't want to know the answer, I just want to know how to solve the problem, but I have no clue where to start. If someone could just help me get the problem started, or in the right direction, I would really appreciate it. Thanks!
 
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i used the conservation of mechanical energy theorem...

[tex] \frac{1}{2} (0.85)v^2 + (0.85)g(0.95) = \frac{1}{2} (0.85)(6)^2[/tex]

...

[tex] v^2 + 2g(0.95) = 36[/tex]

...

[tex] v^2 = 36 - 18.62[/tex]

so...

[tex] v = 4.16893272[/tex]

Well - if u find any mistakes - pls feel free to comment.
 
I saw that formula in my physics book, but I wasn't sure if it would apply to the problem because we haven't really gone over it yet.
But I'm going to use it to solve the problem, because it is a lot more than I had, and I will ask about it tomorrow.
Thanks!
 

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