Determine 3 Elements of Group H with Primes p & q

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Homework Help Overview

The discussion revolves around identifying three specific elements from a set related to distinct prime numbers p and q, within the context of group theory under addition. The group H is defined as a proper subset of integers containing exactly three elements from the set { p, p+q, pq, p^q, q^p }.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore various combinations of elements from the set and question the implications of including certain primes in the group. There is discussion about the properties of groups and the implications of including coprime elements.

Discussion Status

Some participants have provided hints and examples to guide understanding, while others express confusion and seek further clarification. There is an ongoing exploration of the properties of groups and the relationships between the elements involved.

Contextual Notes

Participants note the importance of coprimality and the implications of including certain elements in the group, as well as the constraints of the problem regarding the structure of H.

mansi
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let p and q be distinct primes. suppose that H is a proper subset of integers and H is a group under addition that contains exactly 3 elements of the set
{ p,p+q,pq, p^q , q^p}.
Determine which of the foll are the 3 elements in H
a. pq, p^q, q^p

b. P+q, pq,p^q

c. p, p+q, pq

d. p, p^q, q^p

e. p, pq, p^q
 
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Hint Euclid's algorithm: p^r and q^s are coprime so if H contains these two elements, then it contains 1, and hence is Z. Use this idea in several variations. Of course you could consider the group pZ
 
thanks sir, but could you please elaborate further.
i don't seem to get the idea...
 
If a group contains p, it contains np for all n in Z. So clearly e. forms the answer.

A group for instance cannot contain p and q if they are coprime and not be all of Z since there are a and b in Z such that ap+bq=1, hence the group contains all elements of Z.

And I tihnk you ought to ponder that for a while, cos I really have given you more information than I want to.
 
How about thinking about an example if you cant' see it:

p=2 q=3

If 2 and 3 are in the group, then so is -2 (inverses) and hence, so is 3-2=1 (composition)

If 1 is in there so is 1+1+1+..+1= n (composition) and n was arbitrary, also -n is in there (inverses again)
 
well...thanks a lot, sir! i figured it out...
 

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