Solving Boolean Equations: Tips & What to Do Next

  • Thread starter Thread starter adnankhuram
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around solving Boolean equations, focusing on simplification techniques and next steps in the problem-solving process. Participants share their approaches and corrections related to specific terms and operations within the equations.

Discussion Character

  • Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant questions their approach and seeks guidance on next steps.
  • Another participant confirms part of the work and identifies an EXOR operation in the last two terms, suggesting a reference to an attachment for further simplification.
  • A different participant challenges the correctness of the statement AA = 1 and points out additional possibilities in the equation, specifically mentioning the term ABC + \bar{A}BC.
  • A later reply acknowledges the correction and expresses appreciation for the input.
  • Another participant expresses agreement with the previous work up to a certain point but suggests further simplifications could lead to a form resembling PQ + RS.

Areas of Agreement / Disagreement

Participants express both agreement and disagreement regarding specific steps in the simplification process. There are competing views on the correctness of certain terms and the potential for further simplification, indicating that the discussion remains unresolved.

Contextual Notes

Some assumptions about the validity of certain Boolean identities are not explicitly stated, and there are unresolved mathematical steps regarding the simplification of the equations discussed.

adnankhuram
Messages
3
Reaction score
0
Am i doing right?

And what to do next?
 

Attachments

  • 2.PNG
    2.PNG
    2.2 KB · Views: 463
Physics news on Phys.org
This looks right. The last 2 terms would produce an EXOR operation. Remember:

[tex]A'B+AB' = A\oplus B[/tex]

Nothing else comes to mind when simplifying this further. However you can refer to the attachment if there is anything else you can do.
 

Attachments

[itex]AA = 1[/itex] is not correct.

And there seem to be other possibilities at the top line - consider what is [itex]ABC + \bar{A}BC[/itex] ?
 
Ahh you are right! Nice catch! Haha!
 
Let me encourage a little further and say that I agree with your work until the fourth line, adnankhuram. From there you can make further simplifications to leave something that looks like [itex]PQ+RS[/itex].
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K