i dont understand where i went wrong..please help

[agirlsrepublic]

a velocity selector consists of magnetic and electric fields. if B= 0.015 find the value of E such that a 750 eV electron is moving along the + x- axis and is undeflected.

this is what i did..

the magnetic force=electric force so qvB=qE or vB=E
K= .5 mv^2 and r= mv/qB so k =[.5r^2q^2B^2]/m and if you simplify you get:
r= [(2km)^.5]/qB

r= {[2*750*1.6*E-19*9.11E-31]^.5}/1.6E-19*.015= 1.38E-16

if v=rqm/m then v = [1.38E-6*1.6E-19*.015]/9.11E-31 = 3.64E3

since E= vB then E= 3.64E3*0.15= 5.45E1

but this is not the answer
the answer is 244 KV/m


someone please help its driving me mad and i have a test soon
thanks!

[Doc Al]

the magnetic force=electric force so qvB=qE or vB=E
Right.
K= .5 mv^2 and r= mv/qB so k =[.5r^2q^2B^2]/m and if you simplify you get:
r= [(2km)^.5]/qB
No. K = 1/2 m v^2, so v = \sqrt{2K/m}. Thus E = B \sqrt{2K/m}.

[agirlsrepublic]

thanks..i appreciate it

[dextercioby]

Right.

No. K = 1/2 m v^2, so v = \sqrt{2K/m}. Thus E = B \sqrt{2K/m}.

Well,Doc,for her sake,let's hope she got where your equation with E,B and v came from.If not,i'm willing to explain to her everything in detail.Yet,by the look of her last post,she aint't got a clue. :rolleyes:

[agirlsrepublic]

listen buddy.. if i know that E=vB then i know where he got the equation from

:rolleyes:

[dextercioby]

listen buddy.. if i know that E=vB then i know where he got the equation from

:rolleyes:

Yo,pal, :wink: u definitely didn't show it.Else u wouldn't have gotten yourself in messy & useless calculations.My guess... :tongue2: