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Simple Integral but unknown method
EternityMech
Dec7-11, 10:30 AM
x+1/(x+2)(x+3) = A/x+2 +B/x+3
how do u calculate A and B ?
nevermind i got it thanks.
mathman
Dec7-11, 03:49 PM
R.H.S. = {A(x+3) + B(x+2)}/{(x+2)(x+3)}
Therefore (assuming x+1 should be (x+1)): (A+B)=1 and (3A+2B)=1
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