Solving Omega in Angular Velocity Equations: A Test Prep for Sarah

Click For Summary

Homework Help Overview

The discussion revolves around understanding the role of omega in angular velocity equations within the context of physics test preparation. Participants are exploring the application of angular motion concepts and equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the substitution of linear kinematic variables with their angular counterparts, such as replacing velocity with omega and acceleration with alpha. Questions arise regarding the specific equations and their applications in problems involving angular motion.

Discussion Status

There is an ongoing exchange of ideas about the relationships between linear and angular motion equations. Some participants suggest specific equations and transformations, while others express uncertainty about their usage in different contexts. No explicit consensus has been reached.

Contextual Notes

Participants are preparing for an upcoming test, which may impose constraints on the depth of understanding expected. There is a focus on clarifying definitions and applications of angular motion concepts.

sarahowen
Messages
7
Reaction score
0
we are just about to take a test in physis.. I am quite scared. i have revised on all the topics required but i don't get the use of omega in angular velocity equations. what is the equation and when do i need to use it?
sarah
 
Physics news on Phys.org
well - u can take ur normal kinematics equation and replace v with omega.
like...

[tex] \theta = \theta_0 + \omega t + \alpha t[/tex]

alpha is the angular acceleration.
 
Just learn

v=rw

w= 2.pi.f = 2.pi / T

f = 1/T =w / 2.pi

a = v^2/r = rw^2

F=mv^2/r = mrw^2
 
Replace v by [tex]\omega[/tex]

a by [tex]\alpha[/tex]

and x by [tex]\theta[/tex]

in your kinematics equations to get the rotational equations!

[tex]\omega = \omega_0 + \alpha t[/tex]
[tex]\theta = \theta_0 + \omega_0 t + \frac{1}{2}\alpha t^2[/tex]
[tex]\omega^2 = \omega_0^2 + 2\alpha\theta[/tex]

And the Equations posted by Briton are also very important
 
Last edited:

Similar threads

  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
3K
Replies
335
Views
18K
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
14
Views
3K
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K