derivative x^x^x

[silence]

i can solve x^x but adding this new x just confuses me any help will do, X^x^x

[Lonewolf]

Do you mean (x^x)^x or x^(x^x)? I'm assuming the former.

[silence]

sorry i meant x^(x^x)

[Lonewolf]

Glad you picked that one. Get something like ln(y) = xxln(x) and use the product rule. Don't forget you already know d(xx)/dx [;)]

[silence]

wow i never noticed that i was doing it a long way which would have come out wrong anyways. thanks for the help

[djuiceholder]

ok ok

[arildno]

but can you do (x^x)^x ??
it seems impossible

1. It is not at all imposible; note that this equals: (x^{x})^{x}=x^{x^{2}}
Rewriting this as:
x^{x^{2}}=e^{x^{2}\ln(x)}
We may readily differentate this by means of the chain rule, yielding the derivative:
x^{x^{2}}(2x\ln(x)+x)

2. Please do not re-open nearly 6-year old threads.

[djuiceholder]

ok ok