View Full Version : Two limited integration questions
Peace!
I want to know the conditions that must be satisfied by a function
f(x) for any of the following two cases to be true (each case independent from the other);
1- \int^a_{-a} f(x) dx = 2 \int^a_0 f(x) dx
2- \int^a_0 f(x) dx = \int^0_a f(x) dx
They gave me confusion when I was solving problems related to electric field and electric potential.
quasar987
Dec13-04, 08:52 AM
I don't know if this condition is sufficient but a condition would be, if we write the integrals in terms of their primitives,
\int^a_{-a} f(x) dx = 2 \int^a_0 f(x) dx \Leftrightarrow \mathcal{F}(a) - \mathcal{F}(-a) = 2\mathcal{F}(a) \Leftrightarrow \mathcal{F}(-a) = -\mathcal{F}(a)
The condition is that it is true iff the primitive of f is a function F such that F(-a) = -F(a)
First case...
\int^a_{-a} f(x) dx = \int^0_{-a} f(x) dx + \int^a_0 f(x) dx
Then use the fact that :
\int^0_{-a} f(x) dx = - \int^{-a}_0 f(x) dx
and replace x by -x...the limit -a will then change to a because of this substitution. and dx will become -dx. Now f(x) becomes f(-x) and there are two possibilities. Either f(-x) = -f(x) or f(-x) = f(x)....you know what you will need to achieve so which one of the two is it...
Question 2 :
Just put the integral in right hand side to the left hand side and use the above property to get rid of the minus-sign...what do you get ???
regards
marlon
Can you put like , first case is true if f(x) is even and if such and such....
I shall study your answer. But from my first reading I need more.
I need a condition to apply to f(x) so I can use each of the above properties.
hhegab
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