What is the Impact of a Time-Dependent Force on an Object's Velocity?

Click For Summary

Homework Help Overview

The discussion revolves around the impact of a time-dependent force, specifically F=(8i-4tj) N, on the velocity of a 2 kg object initially at rest. Participants are exploring how to determine the time at which the object reaches a speed of 15 m/s.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss applying Newton's 2nd Law and integrating the force to find velocity. There are attempts to relate acceleration to velocity and questions about the correctness of derived equations.

Discussion Status

Some participants have offered guidance on integration and substitution, while others express confusion regarding their calculations and the resulting quadratic equation. There appears to be a mix of interpretations regarding the correct approach to the problem.

Contextual Notes

Participants note that the problem is set within a calculus-based engineering course, which may influence the methods discussed. There is mention of a quadratic equation arising from the calculations, but uncertainty remains about its correctness.

BbyBlue24
Messages
17
Reaction score
0
A time-dependent force, F=(8i-4tj) N, where t is in seconds is exerted on a 2 kg object initially at rest. At what time will the object be moving with a speed of 15 m/s?
 
Physics news on Phys.org
Use Newton's 2nd Law rearranged in this way:

[tex]\sum_{i=1}^{n} F_{i} = m \frac{dv}{dt}[/tex]

[tex]\sum_{i=1}^{n} F_{i}dt = mdv[/tex]
 
With this problem I figured the Acceleration = Force/Mass = 4i - 2tj. I tried using the equation velocity = at; 15=4i - 2tj which gives me a false answer and is where I am stuck at. Thanks.
 
Integrate

[itex]v_{o} = 0[/itex]

[tex]\int_{0}^{t} 8 \hat{i} - 4t \hat{j} dt = \int_{0}^{v} m dv[/tex]

Note: Are you on a calculus based course?
 
Yes, a calculus based engineering course.
 
Last edited:
Well, then integrate then substitute for v the value 15 m/s and solve the problem.
 
I am still having problems with this problem; I have a quadratic equation of 15^2=16t^2+4t^4, with the time equal to 2.4, but this is not the correct answer, please help, thanks!
 
That's the answer around 2.4 seconds.
 
Thank you!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
6
Views
3K
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
26
Views
5K
Replies
1
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K