Help Solve Hydraulic Problem Involving Spring and Rock

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The forum discussion addresses a hydraulic problem involving a spring with a spring constant of 1456 N/m and a rock weighing 39.4 kg resting on an output plunger. The relationship between the forces and areas of the input and output plungers is established using the equation F1/A1 = F2/A2. The force exerted by the rock is calculated using its mass and gravitational acceleration, and the spring compression is determined using the formula F = kx.

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hydraulic problem, need help!

a hydraulic chamber in which a spring (spring constant = 1456 N/m) is attached to the input piston, and a rock of mass 39.4 kg rests on the output plunger. The piston and plunger are at the same height, and each has a negligible mass. By how much is the spring compressed from its unstrained position?

output plunger=65cm^2
input plunger=15cm^2

i have no clue how to get it started, can anyone help!
 
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Well you have the equation:
[tex]\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}[/tex]

The output plunger has an Area of [tex]65cm^2[/tex] and a force downward of the rock (Mass*Gravitational Accelertaion = Force)

And you know the area of the input plunger.

Also, the force on the spring is [tex]F=kx[/tex]

Solve using that information. Good luck.
 
thanks

thank you so much that really helped a whole lot.

-foggy :smile:
 

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