How to Verify Electromagnetic Field Equations in MTW Gravitation Problem?

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SUMMARY

The discussion focuses on verifying the electromagnetic field equations for an oscillating dipole as presented in MTW Gravitation, specifically equations (4.23) and (4.24). It is established that dF=0 holds true everywhere, while d*F=0 is valid except at the origin. The challenge lies in demonstrating that dF=0 at the origin while d*F≠0 at that point. Participants are seeking alternative methods to simplify the calculations of dF and d*F at the origin for clearer proof.

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Homework Statement



Page. 124, MTW Gravitation. Exercise 4.6.

Verify that the expressions given for the electromagnetic field of an oscillating dipole in equations (4.23) and (4.24) satisfy [itex]<b><i>dF</i></b>=0[/itex] everywhere and [itex]<i><b>d*F</b></i>=0[/itex] everywhere except at the origin.

Homework Equations



(4.23) [itex]<i><b>F</b></i>=[/itex]real part of [itex]\left\{p_1e^{iω(r-t)}[2\cos θ(1/r^3-iω/r^2)dr\wedge dt+\sin θ(1/r^3-iω/r^2-ω^2/r)rdθ\wedge dt+\sin θ(-iω/r^2-ω^2/r)dr \wedge rdθ]\right\}[/itex]

(4.24) [itex]<i><b>*F</b></i>=[/itex]real part of [itex]\left\{p_1e^{i(r-t)}[\sin \theta(-i\omega /r^2-\omega^2/r)dt \wedge r\sin\theta d\phi+2\cos\theta (1/r^3-i\omega /r^2)rd\theta \wedge r\sin\theta d\phi+\sin\theta (1/r^3-i\omega /r^2-\omega^2/r)r\sin\theta d\phi\wedge dr]\right\}[/itex]

The Attempt at a Solution



It is easy to show that [itex]<b><i>dF</i></b>=0[/itex] and [itex]<i><b>d*F</b></i>=0[/itex] everywhere except at the origin. But how to show [itex]<b><i>dF</i></b>=0[/itex] at the origin, while [itex]<i><b>d*F</b></i>≠0[/itex] at the origin?
 
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I tried to calculate dF and d*F at the origin, but I could not get an expression that is easy to be simplified. Is there any other way to prove this statement?
 

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