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chocolatefrog
Jan13-12, 01:52 PM
1. The problem statement, all variables and given/known data

If (I + A) is nonsingular, prove that (I - A)(I + A)-1 = (I + A)-1(I - A), and hence (I - A)/(I + A) is defined for the matrix.

I've proved it like this:

Let (I - A)(I + A)-1 = A, and (I + A)-1(I - A) = B.
B-1 = (I - A)-1(I + A)
B-1A = I
Premultiplying by B, we get A = B.

Is this proof correct?

micromass
Jan13-12, 02:21 PM
1. The problem statement, all variables and given/known data

If (I + A) is nonsingular, prove that (I - A)(I + A)-1 = (I + A)-1(I - A), and hence (I - A)/(I + A) is defined for the matrix.

I've proved it like this:

Let (I - A)(I + A)-1 = A, and (I + A)-1(I - A) = B.
B-1 = (I - A)-1(I + A)
B-1A = I
Premultiplying by B, we get A = B.

Is this proof correct?

You don't know that I-A is invertible. So (I-A)-1 might not exist.

chocolatefrog
Jan14-12, 03:00 AM
You don't know that I-A is invertible. So (I-A)-1 might not exist.

Oh, I forgot to mention that A is known to be skew-symmetric. So, (I - A)T = (I + A), which is nonsingular. And since a matrix is nonsingular iff its transpose is nonsingular, we could assume that (I - A)-1 exists.

I can't seem to think beyond this point. If there's still an error somewhere in the proof, could you please point to it?