View Full Version : derivative
UrbanXrisis
Dec15-04, 06:16 PM
f(x)=2xe^(-x)
what is derivative?
f(x)=(2x)/(e^x)
f'(x)={{2e^x}-{2x^2e^{x-1}}}/(e^x)^2
can I simplify this?
Integral
Dec15-04, 06:19 PM
Recall that:
\frac {d e^x} {dx} = e^x
then apply the chain rule.
Surely easier to do by product rule!
f'(x)=2e^-^x - 2xe^-^x
or even:
f'(x)=(2 - 2x)e^-^x
UrbanXrisis
Dec15-04, 06:35 PM
gee thanks!
The questions acually asks to find each critical point of f and whether f(x) is a relative maximum, relative minimum, or neither. I set f'(x) to zero and solved. I got x=1.
I found it to be a maximum value. Is this correct?
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.