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UrbanXrisis
Dec15-04, 06:16 PM
f(x)=2xe^(-x)

what is derivative?

f(x)=(2x)/(e^x)
f'(x)={{2e^x}-{2x^2e^{x-1}}}/(e^x)^2

can I simplify this?

Integral
Dec15-04, 06:19 PM
Recall that:
\frac {d e^x} {dx} = e^x
then apply the chain rule.

FZ+
Dec15-04, 06:20 PM
Surely easier to do by product rule!

f'(x)=2e^-^x - 2xe^-^x

or even:

f'(x)=(2 - 2x)e^-^x

UrbanXrisis
Dec15-04, 06:35 PM
gee thanks!
The questions acually asks to find each critical point of f and whether f(x) is a relative maximum, relative minimum, or neither. I set f'(x) to zero and solved. I got x=1.

I found it to be a maximum value. Is this correct?