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whats the integral of tan^2(u)(sec(u))du?
i was trying to integrate
(x^2)/sqrt(x^2+1)dx, and came into that. it turns out pretty messy though, is there a clean way to do it?
Hi, I'm usually inclined to convert an integral like that to one with only sin's and cos's:
\int\frac{\sin(u)^2}{\cos(u)^3}du
Integration by parts will work on this if you break it up properly.
dextercioby
Dec18-04, 11:57 AM
\int \frac{x^{2}}{\sqrt{x^{2}+1}} dx =...?
Make the natural substitution: x\rightarrow \sinh y
U'll be gettin' \int \sinh^{2}y dy (1)
Consider the "sister integral" \int \cosh^{2}y dy (2)
Consider the two expressions obtained by:(2)+(1);(2)-(1).The two new integrals will be trivials since u can use the 2 formulae from hyperbolic trigonometry:
\cosh^{2}y-\sinh^{2}y=1;\cosh^{2}y+\sinh^{2}y= \cosh{2y}
In the end u can extract this integral \int \sinh^{2}y dy easily and then in the final result u'll have to make the substitution back
y\rightarrow \arg\sinh x
Daniel.
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