View Full Version : Differentiation
footprints
Dec18-04, 11:20 AM
Given that pV=3600, find the value of\frac{dp}{dV} when p= 40
I don't even know where to start?
Find the value of V when p = 40, then evaluate dp/dV using your value of V.
footprints
Dec18-04, 11:29 AM
Do you mean 40p = 3600?
Sorry I don't understand. My teacher doesn't teach very well.
Do you mean 40p = 3600?
Sorry I don't understand. My teacher doesn't teach very well.
No, set p = 40 so you get 40V = 3600 and solve for V. Then write p in terms of V, differentiate and then plug in your value of V.
dextercioby
Dec18-04, 11:34 AM
Do you mean 40p = 3600?
Sorry I don't understand. My teacher doesn't teach very well.
Vp(V)=3600;p(V)=\frac{3600}{V} .
Question:what is \frac{dp(V)}{dV} ??
Daniel.
footprints
Dec18-04, 11:47 AM
Got it. Thanks. Last question. Why do I have to find V? Or how do I know I have to find V?
Got it. Thanks. Last question. Why do I have to find V? Or how do I know I have to find V?
Well because you're asked to find a value for dp/dV and your expression for dp/dV will be in terms of V and not p.
footprints
Dec18-04, 11:51 AM
Oh right. Thanks a lot. Really appreciate it.
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