View Full Version : Forces in action help...
Hey ppls, how r ya? i have a few questions ...
Questions (http://www.boomspeed.com/asianedz/Untitled.jpg)
yeh i have the resolution to it although it is my friends one. i dun really understand how he got it... can some1 plz explain to me clearly how he did it and if the answer is right?
here are the resolution...
Question 22 (http://www.boomspeed.com/asianedz/Untitled2.jpg)
Question 23 (http://www.boomspeed.com/asianedz/Untitledm.jpg)
thanks in advance..
EdZ
first show where you got stuck (policy)
then we'll be glad to help
actually forget that one, i read it a few times over again and i understood how to do it.
but i do have one question, i was wondering
what is the procedure to find the error on an equation..
for e.g.
4.7 +- 0.5 * 45.64 +- 0.21 / 32.233 +- 0.923
what are the steps in identifying where the error is.?
The easiest way I've found is to keep the units on your numbers. (I must sound like a broken record... I've said this three times since we switched to the new forums alone)
If you are adding, all summed units must be the same.
All units must also be the same on both side of the equality sign.
sorry, i dont quite understand what your saying... can u please explain again...
sorry, :(
For example,
In your friend's solution for the first problem.
Instead of writing 20-3a=2a
write 20 N - 3kg*a = 2kg*a
You know then, that every term is the same.
It's not a big thing for a simple problem like this, but once you get more things in there, it's an easy way to check yourself.
If the units don't add up on both sides of the equal sign, you've made a mistake.
ahh ok ok... im with u now... i thought u were talking about my other question which was to do with error analysis...
yes i will keep that in mind.. thankyou!
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