What force does Pete exert on the rope?

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Homework Help Overview

The problem involves calculating the force exerted by Pete on a rope while dragging a crate across a horizontal surface at a constant speed. The crate requires a horizontal force of 809 N, and the rope is held at an angle of 33°.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need for clarification on the formula to use, with some suggesting the application of trigonometry and the use of right triangle relationships to find the force exerted by Pete.

Discussion Status

Several participants have offered guidance on using trigonometric relationships and drawing diagrams to visualize the problem. There is an ongoing exploration of different approaches, but no consensus has been reached on a specific method or solution.

Contextual Notes

Participants note the importance of understanding the relationship between the forces acting on the crate and the angle of the rope. There is an emphasis on the need for clarity in the original poster's understanding of the problem setup.

Kdawg
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How would I calculate this
A horizontal force of 809 N is needed to drag a crate across a horizontal floor with a constant speed. Pete drags the crate using a rope held at an angle of 33°. What force does Pete exert on the rope?
 
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How about show some working, so we can help you on where you're stuck?

Remember this forum does not do your homework :smile:
 
I was wondering what the formula was?
 
i think u missed some ideas in ur homework. pls clarify it. i think it is work.
 
Use a bit of trigonometry. I'm sure you've learned trigonometry in class.
 
Just think of it as a triangle.

The floor is one length (A) and the rope it the other(H), in this case we make pete the other(O). since we have the angle and we want the length of H we use the following formula. sin33=A/H therefore A/sin33=H just carry on from here.
 
Draw a diagram of th situation. Draw the forces acting on the crate. in this case, since it's moving at constant speed, there is no acceleration.

since the rope is at 33 degrees, it would be a right angled triangle with the adjacent of the 33-degree angle being of magnitude 809

from there, u can use the cosine formula to calculate the hypotenuse of the triangle, which will give u the force exerted by Pete!
 

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