Probability of Rolling Sum > 8 w/ Dice: Calculating Probability & Avg Rolls

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Homework Help Overview

The discussion revolves around calculating the probability of rolling a sum greater than 8 with a pair of dice, specifically focusing on the number of rolls required to achieve this outcome. Participants are exploring the implications of probability calculations in this context.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the method of multiplying probabilities to determine the likelihood of achieving a sum greater than 8 within a specified number of rolls. There is discussion about the interpretation of events and whether they are independent.

Discussion Status

The conversation is ongoing, with participants expressing uncertainty about the correct approach to calculating probabilities. Some have attempted to clarify their understanding, while others are seeking further explanation and guidance on the topic.

Contextual Notes

There are assumptions about the independence of events in rolling dice, and participants are grappling with the implications of these assumptions on their calculations. The original poster has indicated a desire to create a table of probabilities based on the number of rolls.

KingNothing
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A pair of dice is being rolled. The probability for rolling a sum greater than 8 is 10/36.

Is the probability for it taking two rolls to attain a sum greater than 8 just 26/36 times 26/36?

I need to make a table of the number of rolls it takes to obtain a sum greater than 8, and the probability that it will take that many rolls. What equation do I use? Assume n is the number of rolls it takes.

EDIT: I think I figured it out as I was walking away from the comp. Is it (26/36)^(n-1) * (10/36)?

Assuming it is, how do you find the average number of rolls it takes to get that? It looks to be about 2.4. But how do I calculate that? Is it just 36/10 or 3.6?
 
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KingNothing said:
Is the probability for it taking two rolls to attain a sum greater than 8 just 26/36 times 26/36?

Umm...but the thing is...I interpret the sentence "the probability that it will take two rolls to attain a sum > 8" to mean that you actually get a sum greater than 8 on the second roll. Otherwise, it would take 3 or more rolls! So why did you multiply by 26/36 the second time?

In general, I am not sure about the strategy of multiplying the probabilities together. Wouldn't you expect the probability of obtaining a sum > 8 to increase with larger n? Yet, if you multiply the probabilities, the product only gets smaller.

Yeah, they are not independent events, because if you consider the events independent and multiply the probabilities together (using your formula)...you are calculating the chances of getting a sum less than eight exactly n-1 times, followed by a sum > 8 the nth time. So that's NOT the way to do it.

I'll have to think about it more. No doubt somebody will explain how to do it before I figure it out.
 
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when you said you roll two times... how is it differ from rolling 4 dices at the same time? ... hope this answer your question...
 
vincentchan said:
when you said you roll two times... how is it differ from rolling 4 dices at the same time? ... hope this answer your question...

It just makes it more complicated to think of rolling four dice and dealing with sums greater than 8.
 
what grade r u in?
 
Is the probability for it taking two rolls to attain a sum greater than 8 just 26/36 times 26/36?

are u saying the sum of two rolls is greater than 8, or both rolls is greater than 8?
 

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