Solve the Energy Homework Problem: Tarzan's Speed on a 30m Vine

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Homework Help Overview

The problem involves calculating the speed of Tarzan at the bottom of a swing on a 30m vine, starting from rest and initially inclined at an angle of 37 degrees with the vertical. The subject area pertains to energy conservation in physics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the conservation of energy principle using the equation 1/2mv^2 = mgh but struggles with the angle's impact on height. Some participants suggest analyzing the geometry of the problem to determine the correct height (h) in relation to the angle and vine length.

Discussion Status

Participants are actively discussing the setup of the problem and the correct interpretation of height in the energy equation. There is engagement around refining the approach, with some guidance provided regarding the geometric considerations necessary for solving the problem.

Contextual Notes

There is an emphasis on not providing direct answers, with participants encouraged to explore their reasoning and clarify assumptions related to the geometry of the swing and energy conservation.

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i started to do this engery problem we got for homework but when i tried to solve it i got the wrong answer. could someone please tell me how to begin this problem?

Tarzan swings on a 30m long vine initially inclined at an angle of 37 degree with the vertical. What is his speed at the bottom of the swing if he starts from rest??
 
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What's your opinion??Post your work...Read the "sticky".We don't nobody' s homework.We only help if people get stuck.But you haven't even started.

Daniel.
 
i did start it i used the equation 1/2mv^2=mgh but then since their is an angle i tried to do it that way but i got the wrong answer. i don't5 expect anyone to do my homework or else it would be useless to do.
 
The equation u've written is principially good,but it needs "polishing".Think/analyze the geometry of the problem and try to see which is "h" u need in that equation and its connection with the length and the angle the problem speaks about.

Daniel.
 
i tried using 30cos37 but that doesn't work so then i tried using 30sin37 and that doesn't work either so i wonder if i am doing something wrong
 
That "h" is the difference in heigh/elevation between the lowest point of the circular trajectory and the upper one.Assume that the "0" (origin) for the potential energy is chosen to be the lowest point of the trajectory.

Daniel.
 
so are u saying i should subtract what i get from the cos/sin from the 30?
 
thx that did work! Now could u help me on my other post please :biggrin:
 

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