If the ball revolves twice every second, what is the tension in the string?

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Homework Help Overview

The problem involves a 0.25-kg ball rotating in a horizontal circle with a radius of 0.5 m, revolving twice every second. The discussion centers on determining the tension in the string that holds the ball.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore how to calculate the velocity of the ball based on the given information, the relationship between velocity and centripetal acceleration, and how centripetal acceleration relates to the tension in the string.

Discussion Status

Some participants have provided equations related to the problem, while others express uncertainty about their correctness. There is a request for step-by-step assistance, indicating that the discussion is ongoing and participants are seeking clarification on the concepts involved.

Contextual Notes

One participant mentions limitations in accessing resources due to being at work, which may affect their ability to engage fully with the problem.

Alexs45
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A 0.25-kg ball attached to a string is rotating in a horizontal circle of radius 0.5 m. If the ball revolves twice every second, what is the tension in the string?
 
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1) How can you figure out the velocity of the ball by the information given?
2) How is that velocity related to the centripetal acceleration experienced by the ball?
3) How is the centripetal acceleration of the ball related to the tension in the string?
 
[tex]v = \frac{2 \pi r}{T}[/tex]
[tex]a_c = \frac{v^2}{r^2}=\frac{4 \pi^2 r}{T^2}[/tex]
[tex]m \cdot a_c = F_T + F_g[/tex]
i don't know if that's it, because I am kind of limited on my sources. I am at work, and I am not even supposed to be on this site. :smile: the last equation is probably wrong, but i know the first two are right. well, i think. :smile:
 
Last edited:
i don't think that is right, i need the step by step help
 
all you have to do is plug in the numbers.
 

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