How Is Tension Calculated in a Plucked Telephone Cord?

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Homework Help Overview

The discussion revolves around calculating the tension in a telephone cord based on the properties of wave motion. The original poster presents a problem involving a transverse wave pulse and expresses frustration over incorrect calculations despite following a formula.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply a formula relating time, tension, and linear density but questions their understanding of the variables involved. Another participant prompts clarification on the meaning of 't' in the context of the problem.

Discussion Status

The conversation is ongoing, with participants exploring the correct interpretation of the formula and the variables involved. Some guidance has been offered regarding the correct relationship between tension and linear density, indicating a productive direction in the discussion.

Contextual Notes

Participants are working under the constraints of specific problem parameters, including the length and mass of the cords, and the time taken for wave pulses to travel. There is an emphasis on understanding the implications of the problem statement regarding the number of trips made by the wave pulse.

nemzy
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A telephone cord is 4.00 m long and has a mass of 0.300 kg. A transverse wave pulse is produced by plucking one end of the taut cord. The pulse makes three trips down and back along the cord in 0.700 s. What is the tension in the cord?


ok, this problem seems very easy and straightforward but i am getting it wrong..i have absolute no idea why ..i hate physics can't wait till i finish this damn course...

anyways...

t=time
T=tension
u=mass/length
L=total length

t=L*sqrt(u/T)

simple, and just solve for T right? But i am getting it wrong why??

t=.7 sec
u=(.300 kg/4 m)
L= 3*(4 m)

i have all the variables but T and solve for T and get 22.03 N

but the answer is wrong does any 1 know where i went wrong thx
 
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nemzy said:
A telephone cord is 4.00 m long and has a mass of 0.300 kg. A transverse wave pulse is produced by plucking one end of the taut cord. The pulse makes three trips down and back along the cord in 0.700 s. What is the tension in the cord?


ok, this problem seems very easy and straightforward but i am getting it wrong..i have absolute no idea why ..i hate physics can't wait till i finish this damn course...

anyways...

t=time
T=tension
u=mass/length
L=total length

t=L*sqrt(u/T)

simple, and just solve for T right? But i am getting it wrong why??

t=.7 sec
u=(.300 kg/4 m)
L= 3*(4 m)

i have all the variables but T and solve for T and get 22.03 N

but the answer is wrong does any 1 know where i went wrong thx


Yes. What does 't' represent in your formula ? You said it is the time, but it's the time taken for what ? Where did you find that formula ?

Read this part again, carefully :
The pulse makes three trips down and back along the cord in 0.700 s.
 
I'm also doing a similar problem.
An ethernet cable is 4.10 m long and has a mass of 0.210 kg. A transverse pulse is produced by plucking one end of the taut cable. The pulse makes four trips down and back along the cable in 0.815 s. What is the tension in the cable?

please help!
 
I am not positive of the answer to your question, but one thing that might help is its actually the square root of T/u tension divided by the linear density not linear density divided by tension
 

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