Can we do this with greater than sign

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Homework Help Overview

The discussion revolves around the inequality involving a product of binomials, specifically the expression (2x-9)(x+3) ≥ 0. Participants are exploring the implications of the "greater than or equal to" sign in relation to solving the inequality.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Some participants consider whether it is valid to separate the factors of the product into individual inequalities. There is uncertainty about the implications of the inequality sign when doing so. Others suggest that both factors could be negative, raising questions about the conditions under which the product remains non-negative.

Discussion Status

The discussion is ongoing, with participants providing hints and exploring different interpretations of the inequality. There is no explicit consensus, but some guidance has been offered regarding the conditions for the factors.

Contextual Notes

Participants are navigating the constraints of the problem as part of their homework, indicating a focus on understanding the rules governing inequalities.

Ryoukomaru
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Can we do this with "greater than" sign

If [tex](2x-9)(x+3)\geq0[/tex] then can we say [tex](2x-9)\geq0[/tex] and [tex](x+3)\geq0[/tex] and solve them separately ? I am not sure if i can do this because of the [tex]\geq[/tex] sign.

Hmm wrong section. Actually this is part of my homework anyway. :biggrin:
 
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Yeah you can do that because you are dividing both sides by the binomials and 0/ by anything equals 0.
 
The product will also be positive if both factors are negative.
 
If [tex](2x-9)(x+3)\geq0[/tex] then can we say [tex](2x-9)\geq0[/tex] and [tex](x+3)\geq0[/tex] and solve them separately ? I am not sure if i can do this because of the sign.
this is part of the solution only...
Hints
could both values inside the bracket be negative?
 
Thx a lot all and thanks again for the hint.
 

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