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LakeMountD
Jan18-05, 11:26 PM
Using the equation E= (kq)/(R)^2 in the r direction. I am confused on when to make the vector negative in my equations. For instance if you had a charge on x=0 and x=5 (on the x axis) and then you want to find the field at point (1,1) or something like this.

dextercioby
Jan18-05, 11:33 PM
Consider an electric charge "q" in the origin of the coordinate system.The electric field at at a point of coordinate vector \vec{r} is

\vec{E}=\frac{q}{4\pi\epsilon_{0}\epsilon_{r}|\vec {r}|^{2}}\frac{\vec{r}}{|\vec{r}|}

That's all.

Daniel.

Tide
Jan18-05, 11:36 PM
The direction of the vector is the same as the direction from the source point to the field point - multiplied by the sign of the charge.