The discussion focuses on calculating the minimum and maximum speeds of a ball being whirled in a vertical plane using a string. The minimum speed at the top of the motion, denoted as Vmin, is determined by setting the tension in the string to zero and applying Newton's second law. Conversely, the maximum speed at the bottom of the motion, referred to as Vmax, is calculated by setting the tension to Tmax and again using Newton's second law to account for centripetal acceleration.
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I don't know what you mean by "leaving" the string. I suspect the question is "what's the minimum speed at the top of the motion that will keep the string taut". (Or do you mean "what's the minimum speed at the top of the motion that will break the string"?)PhysKid24 said:a ball is whirled around with astring in the vertical plane. at the top of th ewhirl, what is the minimum speed which the ball can have before leaving the string?
You apply Newton's 2nd law, realizing that the ball is centripetally accelerated.do you do sum of the forces and just set v = vmin?
Again, as Gokul43201 explains, apply Newton's 2nd law. But realize that the ball is centripetally accelerated.Then it says the maximum tension the string can have at the bottom is Tmax, what is vmax, the maximum speed of the ball without breaing the string, is it again sum of the forces?