Finding Unit Vectors for Angle of pi/3 in R3

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Homework Help Overview

The problem involves finding unit vectors in R3 that form an angle of pi/3 with two given vectors, (1,0,-1) and (0,1,1). The context is within vector mathematics, specifically focusing on angles and unit vectors.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using the dot product to determine angles between vectors and suggest setting up equations based on the constraints of the problem. There is mention of translating verbal restrictions into algebraic equations.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to formulate the problem mathematically. Some have identified the angle between the given vectors and the desired unit vectors, while others are working on expressing the constraints in terms of equations. There is no explicit consensus on the solution yet.

Contextual Notes

Participants note that the unit vector must satisfy multiple conditions, including being a unit vector and forming specific angles with the given vectors. There is also mention of confusion regarding the correct answer and the process to reach it.

gunnar
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There are two vectors (1,0,-1) and (0,1,1)
I need to find all the unit vectors x in R3 that make an angle of pi/3 with each of the vectors above.

Can someone please help with this problem?
 
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hint:
use dot product to find the angle between vectors
 
You should be able to use the three constraints on your solution vector (unit vector, specified angle with a vector, specified angle with another vector) to write down three equations in the components of your solution vector. Then, solve.
 
O.K I figured out that the angle between the given vectors is 60 degrees or pi/3

The angle between the unit vectors and each of the given vectors is supposed to be pi/3 also. So I used the dot product to calculate

c=sqrt(2) since the unitvector has length 1 and both the given vectors have the length sqrt(2)

Don't seem to be able to get the right answear.
The correct answear is (1/sqrt(2), 1/sqrt(2), 0) only one vector.

How to reach that conclusion I have no idea
 
Lets call the components of the vector you seek (a,b,c). Now there are three restriction on these three numbers. So when you write down the tree restrictions Hurkyl gave in terms of a,b and c you have three equations with three unknowns which you can solve. Can you translate the restrictions from words to algebra?
 

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