Solve Trigonometry Equation: Tan 285° + Cos 75° + Cot 60°

  • Context: High School 
  • Thread starter Thread starter markm
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Discussion Overview

The discussion revolves around finding the exact value of the expression tan 285° + cos 75° + cot 60°. It includes attempts to convert angles to radians and explore identities related to trigonometric functions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents the problem and mentions converting angles to radians, expressing concern about missing important steps.
  • Another participant clarifies that "exact value" means no decimal places.
  • A participant suggests analyzing 5pi/12 as a combination of pi/3 and pi/4, proposing a method to express it as a linear combination of these angles.
  • Further exploration of the reduction formulas for tan(a-b) and cos(a-b) is suggested, but not explicitly detailed.
  • One participant comments on a perceived double post, indicating a potential issue with the thread's organization.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the best approach to solve the problem, and there are indications of confusion regarding the organization of posts.

Contextual Notes

The discussion includes attempts to apply trigonometric identities and methods for angle reduction, but specific identities or formulas are not fully explored or agreed upon.

Who May Find This Useful

Students preparing for tests in trigonometry or those interested in exploring trigonometric identities and angle conversions.

markm
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the question is: find the exact value of tan 285 deg + cos 75 deg + cot 60 deg

i tried converting them to radians and got

tan 5pi / 12 + cos 5 pi / 12 + cot pi / 3

as far as i know, only the cot part has some special identity. am i missing something important? we have a long test tomorrow..

thanks in advance for any help. ^_^
 
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oh, and by exact value the question means no decimal places.
 
RULE NUMBER ONE ON THIS FORUM:

DON'T DOUBLE POST!

Daniel.
 
I didn't see a double post so I won't comment on that.

The denominator in "5pi/12" is 12= 3*4. Hmm, pi/3 and pi/4 tend to be pretty easy!

Can we "analyze" 5pi/12 as a combination of pi/3 and pi/4? That is, can we find
m and n so that 5pi/12= mpi/4+ npi/3? If we multiply that equation by 12/pi, we get
5= 3m+ 4n. Now I think it's just a matter of "trial and error" (actually, there are methods of solving such "Diaphontine equations" but trial and error works here).Trying a few possibilities shows that m= -5, n= 5 gives 3(-5)+ 4(5)= -15+ 20= 5.

Excellent: 5pi/12= 20pi/12- 15pi/12= 5(pi/3)- 5(pi/4) so tan(5pi/12)= tan(5(pi/3)- 5(pi/4) and cos(5pi/12)= cos(5(pi/3)- 5(pi/4)).

Now, do you know any formulas for reducing tan(a-b) and cos(a-b)?
 
The same problem,the same "author" and the same me giving the same hint in the HS Homework section...

Daniel.
 

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