Root3: Rewrite & Produce Non-trivial Equation + Show Irrationality

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Discussion Overview

The discussion revolves around rewriting the expression for \(\sqrt{3} - 1\) to derive a non-trivial equation for \(\sqrt{3}\) in terms of itself and exploring implications for its rationality. Participants engage with mathematical reasoning and propose various formulations and definitions related to the problem.

Discussion Character

  • Mathematical reasoning
  • Exploratory
  • Conceptual clarification

Main Points Raised

  • One participant suggests rewriting \(\sqrt{3} - 1\) as \(\frac{2}{1+\sqrt{3}}\).
  • Another proposes that this leads to the equation \(x - 1 = \frac{2}{x + 1}\) for \(\sqrt{3}\).
  • A participant questions the definition of "non-trivial" in this context.
  • There is a suggestion that if \(\frac{m}{n} = \sqrt{3}\), then \(\frac{m}{n} - 1 = \frac{2}{\frac{m}{n} + 1}\) could lead to further insights.
  • Another participant considers any equation other than \(x = \sqrt{3}\) to be "non-trivial."
  • A later post introduces the expression \(\sqrt{3} = \frac{m + 3n}{m + n}\) and questions whether this leads to any contradictions if \(m\) and \(n\) share a common factor.
  • One participant expresses curiosity about the implications of question 3) for general knowledge.

Areas of Agreement / Disagreement

Participants have differing views on what constitutes a "non-trivial" equation and whether the proposed formulations lead to contradictions regarding the rationality of \(\sqrt{3}\). The discussion remains unresolved with multiple competing perspectives on the definitions and implications presented.

Contextual Notes

Some assumptions regarding the definitions of "non-trivial" and the conditions under which \(m\) and \(n\) are considered may not be fully articulated, leading to potential ambiguities in the discussion.

flying2000
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1)write root(3)-1 in another way,and use this to produce a non-trivial equation for root(3) in terms of itself

2)suppose m,n(m,n is natural numbers) are such that m/n=root(3),use (1) to write root(3)as another combination of m and n.
3)use (2) to show that root(3) in not rational.

Any hints appreciated..
 
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How about

[tex]\sqrt 3 - 1 = \frac {2}{1+\sqrt 3}[/tex]?
 
Which, I think, would then give [itex]x- 1= \frac{2}{x+1}[/itex] as a non-trivial equation for [itex]\sqrt{3}[/itex].

If [itex]\frac{m}{n}= \sqrt{3}[/itex], then [itex]\frac{m}{n}-1= \frac{2}{\frac{m}{n}+1}[/itex]. Does that lead to anything?
 
Hmm. How do you define non-trivial?
 
thanx a lot!

thanks a lot to all you guys!
really appreciated..



HallsofIvy said:
Which, I think, would then give [itex]x- 1= \frac{2}{x+1}[/itex] as a non-trivial equation for [itex]\sqrt{3}[/itex].

If [itex]\frac{m}{n}= \sqrt{3}[/itex], then [itex]\frac{m}{n}-1= \frac{2}{\frac{m}{n}+1}[/itex]. Does that lead to anything?
 
I would consider anything other than [itex]x= \sqrt{3}[/itex] to be "non-trivial"!
 
Another question

HallsofIvy said:
I would consider anything other than [itex]x= \sqrt{3}[/itex] to be "non-trivial"!

root(3)=(m+3n)/(m+n), if m,n is allowed having the common factor,Does it lead to any contradiction?
 
i was wondering wut the answer would be for question 3) for general knowledge
 

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