How Do You Solve Linear Systems with Irrational Numbers Precisely?

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Homework Help Overview

The discussion revolves around solving a linear system that includes irrational numbers, specifically focusing on the methods for achieving precise solutions versus using a calculator. Participants are exploring the implications of irrational numbers in the context of linear algebra.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning how to solve the system precisely without approximating the irrational numbers. There is discussion about the potential differences in outcomes when using a calculator versus a precise method. Some are considering the implications of linear dependence in the equations presented.

Discussion Status

The conversation is ongoing, with participants sharing their thoughts on the nature of the problem and the role of calculators in solving such systems. There is recognition of the challenges posed by irrational numbers, and some guidance has been offered regarding the use of determinants and Cramer's rule, although not all participants agree on the implications of these methods.

Contextual Notes

Participants note that the professor may be highlighting the limitations of calculators in representing solutions involving irrational numbers. There is also mention of homework constraints, such as the requirement to use determinants, which has not been covered in class.

adc85
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One of the questions on a handout was this:

Solve the following linear system:

[2 1 : 4 ]
[2*sqrt of 3 sqrt of 3 : 4*sqrt of 3]

A) Precisely B) With a calculator.

Since this linear system contains irrational numbers, how would you solve it "precisely"? How would the answer be any different than if a calculator was used? Do I just leave alone the irrational square root terms and express the answer like that? Thanks for any help.
 
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adc85 said:
One of the questions on a handout was this:

Solve the following linear system:



A) Precisely B) With a calculator.

Since this linear system contains irrational numbers, how would you solve it "precisely"? How would the answer be any different than if a calculator was used?
Your solution may contain irrational numbers. Most calculators only display rational approximations (as some finite decimal).
Do I just leave alone the irrational square root terms and express the answer like that?
Unless you can find another way of expressing them that is not an approximation, yes. :)
 
Maybe the professor is trying to show you what happens when you solve a system like that with a calculator. I don't know what happens when you try to solve that with a calculator, but since the above works for all x,y in R I would guess that the calculator can't represent this solution or something. The professor might therefore be trying to show you the dangers of using a calculator to solve systems of equations. Just a guess :/

EDIT: Why it works for all x,y in R--multiply top by -sqrt(3)
 
If you multiply the first equation by sqrt(3), you will see that the two become identical. This means that they are linearly dependent and there will be NO unique solution. There will actually be an infinite number of solutions. Maybe that is what your prof was trying to show.
 
Parth Dave, so what about the calculator part? Would it hold true for the calculator part too? How would I know?

Also, if I had problem like:

[4*sqrt of 3 5 : 2 ]
[5 sqrt of 13 : 1 ]

What approach do I need to take here (same subject on solving precisely and solving by calculator)? I have to solve using determinants. He never covered this in class yet it's on the homework.
 
Well if you have to solve it using determinants then you probably need to solve it using Cramer's rule.
 
I tried that with the precise method by leaving alone the irrational numbers (keeping the square roots the way they are). And I end up with this really really long term that just doesn't seem right you know? Thanks for your help though.
 

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