What is the probability that a customer gets at least a 40% discount?

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The discussion revolves around a probability problem related to a promotional sale at a sporting goods store, specifically focusing on the "Wheel of Savings" and the various discount outcomes for customers. The original poster presents multiple probability calculations regarding different discount scenarios.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate probabilities for various discount scenarios based on the distribution of regions on the wheel. Some participants question the interpretation of "at least" in the context of the first problem.

Discussion Status

The discussion includes an affirmation from one participant regarding the original poster's calculations, while another participant seeks clarification on the meaning of "at least" in the probability context. This indicates an ongoing exploration of the problem's assumptions and definitions.

Contextual Notes

The original poster's calculations are based on the specific setup of the discount wheel, which includes different regions for various discount percentages. There is a focus on understanding the implications of the phrasing in the problem statement.

mutzy188
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I'm really not good at probability and I would appreciate it if someone could check to see if I'm doing this right. Thanks

A sporting goods store announces a "Wheel of Savings" sale. Customers select the merchandise they want to purchase, then at the cash register they spin the wheel to determine the size of the discount they will receive. The wheel id divided into 12 regions, like a clock. Six of those regions are red, and award a 10% discount. The three white regions award a 20% discount and two blue regions award a 40% discount. The remaining region is gold, and a customer whose lucky spin lands there gets a 100% discount-the merchandise is free!

1. What is the probability that a customer gets at least a 40% discount?
Work:
(3/12) = 25%

2. What is the probability that 2 customers in a row get only 10% discounts?
Work:
(6/12)(6/12) = 25%

3. What is the probability that 3 consecutive customers all get 20% discounts?
Work:
(3/12)(3/12)(3/12)= 1.6%

4. What is the probability that none of the first 4 customers gets a discount over 20%?
Work:
(9/12)(9/12)(9/12)(9/12) = 31.6%

5. What is the probability that the first gold winner (100%) is the fifth customer in line?
Work:
(11/12)(11/12)(11/12)(11/12)(1/12)= 5.89%
6. What is the probability that there is at least one gold winner among the first six customer?
Work:
1-[(11/12)(11/12)(11/12)(11/12)(11/12)(11/12)] = 40.6%

Is this correct? Thanks
 
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Looks perfect to me. :cool:
 
for number 1 does the "at least" mean anything??
 
It means anything equal to or more than 40%. In this case, it would be 40% or 100% (total of 3 possibilities).
 
ok thanks :smile:
 

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