Calculating Ice Melt from Heat Generated by a 54kg Skater Skating at 6.4 m/s"

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Homework Help Overview

The discussion revolves around calculating the amount of ice melted due to the heat generated by a 54kg skater who stops after skating at a speed of 6.4 m/s. The problem involves concepts from thermodynamics and energy transfer.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculations related to kinetic energy and heat transfer, with one participant expressing doubt about the small amount of ice melted. Others question the assumptions made regarding the latent heat of fusion and the expected results.

Discussion Status

Some participants have provided feedback on the calculations, with one confirming the correctness of the latent heat unit. The conversation reflects a mix of verification and exploration of the implications of the results.

Contextual Notes

There is a mention of the latent heat of fusion for ice and the percentage of heat transferred to the ice, which may influence the interpretation of the results. Participants also express surprise at the calculated amount of ice melted, suggesting a potential misunderstanding of the physical scenario.

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A 54kg ice skater skating at 6.4 m/s stops. If 50% of the heat generated is transferred to the ice, calculate how much ice is melted.

My solution:

(54 x 6.4^2)/2 = 1106 J

1106 x 0.5 = 553 J

553 = m x 3.33 x 10^5 (3.33 x 10^5 is latent heat of fusion of ice)

m = 1.6 grams

It sounds too small to be true, can someone verify please?
 
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If the unit for ice melting latent heat is J/Kg,then it's okay...

Why surprised??

Daniel.
 
Link,

You are correct.

- Warren
 
Hey, you can hardly expect the whole skating rink to melt just because one skater comes to a halt!
 
lol thanks guys! I tend to doubt my calculations sometimes... I was expecting something on 10 grams :smile:
 

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