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Simple pendulum has T = 2pi rt (l/g) when oscillating at a natural frequency of vibration. (Small angles of course)
Calc. new T of pendulum when oscillating in a car with acceleration a.
Any tips? Thanks. :)
Can anyone do this question? Cheers.
T=2\pi \sqrt{\frac{l}{\sqrt(a^2+g^2)}}
Cheers Clive - Would you mind explaining (or any1 else) how you arrived at that answer? thanks.
You may find this explanation (of a similar problem) useful: http://www.physicsforums.com/showpost.php?p=377511&postcount=9
Thanks very much, it certainly was! I understand that totally! You found the effective g acting on the pendulum by summing the individual accelerations acting on the pendulum, using vectors. Great. :)
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