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ProBasket
Feb15-05, 04:08 AM
\int_9^{inf} \frac{1}{x^{6/5}}

first thing i did was found the integral of the function

\frac{5}{x^{-1/5}}

then plug in inf(i will name it b) and 9

\frac{5}{b^{-1/5}} - \frac{5}{9^{-1/5}}
now i will find the lim -> inf

well for \frac{5}{9^{-1/5}}, it's equal to 7.759

now for \frac{5}{b^{-1/5}}, it looks like INF, but when i try to submit my answer, it tells me that i'm wrong.

anyone know what i'm doing wrong?

Muzza
Feb15-05, 04:32 AM
The primitive function is wrong, it should be

-\frac{5}{x^{1/5}}.

dextercioby
Feb15-05, 08:24 AM
Therefore,not only the limit,but also the numerical value for 9 is wrong...You should have written the integrand as x^{-\frac{6}{5}} .

Daniel.