Integration

[briton]

quite simple but need some help:

∫ x/(4-x) dx.


when there's ∫f'(x)/f(x) you can use natural log but waht about this


full workings or some tips anyone?


Thanks.

[arildno]

Hint: Add to the numerator 0=4-4

[briton]

erm so you get
∫ 4/(4-x) dx - ∫1 dx ?

[arildno]

That was the idea, yes.

[briton]

cheers!






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