Magnetism: Solving Force Problem with qvB Equation

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SUMMARY

The discussion centers on calculating the magnetic field using the qvB equation, specifically for an electron moving at 2.0x106 m/s in a magnetic field. The force experienced by the electron is 2.3x10-12 N, directed upward. The correct formula to determine the magnetic field (B) is B = F/(qv), where q is the charge of the electron (1.6x10-19 C). The initial calculation presented was incorrect due to a misunderstanding of the formula's arrangement.

PREREQUISITES
  • Understanding of the qvB equation in electromagnetism
  • Knowledge of the charge of an electron (1.6x10-19 C)
  • Familiarity with unit analysis in physics calculations
  • Basic concepts of magnetic fields and forces on charged particles
NEXT STEPS
  • Review the derivation of the qvB equation in electromagnetism
  • Practice calculations involving magnetic fields and forces on charged particles
  • Explore the implications of Lorentz force in different contexts
  • Investigate the role of directionality in magnetic field calculations
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Students and professionals in physics, particularly those studying electromagnetism, as well as educators looking for practical examples of applying the qvB equation in problem-solving scenarios.

Axeman2k
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I am currently working on a problem that states...
An electron experiences the greatest force as it travels 2.0x10^6 m/s in a magnetic field when it is moving southward. The force is upward and of magnitude 2.3x10^-12 N. What is the magnitude and direction of the magnetic field?

I started with the equation F=qvB and came out with B=(qv)/F since I am trying to find the magnitude of the magnetic field. That calculates to
B=((1.6x10^-19)(2x10^6))/(2.3x10^-12) but does not come out to a correct awnser. Is there anything I am doing wrong?
 
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It should be F/qv. To catch mistakes like this, you should use units in your work, or at least keep them in mind.
 
oops, thanks for catching that
 

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