stunner5000pt
- 1,447
- 5
COnsider a large horizontal frictionless area on the Earth at phi degrees northern latitude. Through an impulse a particle is set in motion with velocity v and then left to move freely ignore all forms of friction. Find the period in the uniformcircular motion of the particle
velocity [tex]v = \omega r[/tex]
[tex]v_{x} = v cos \phi[/tex]
[tex]v_{y} = v sin \phi[/tex]
[tex]v_{z} = 0[/tex]
not sure about the z part...
period [tex]T = \frac {2 \pi }{\omega sin \phi}[/tex]
sin phi because the Y axis the one about which this motion is going about..
I am off by a factor of 2 the answer is [tex]T = \frac{\pi}{\omega sin \phi}[/tex]
velocity [tex]v = \omega r[/tex]
[tex]v_{x} = v cos \phi[/tex]
[tex]v_{y} = v sin \phi[/tex]
[tex]v_{z} = 0[/tex]
not sure about the z part...
period [tex]T = \frac {2 \pi }{\omega sin \phi}[/tex]
sin phi because the Y axis the one about which this motion is going about..
I am off by a factor of 2 the answer is [tex]T = \frac{\pi}{\omega sin \phi}[/tex]