Is Simpson or Trapezium Rule Better for Calculating Area Under a Curve?

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Homework Help Overview

The discussion revolves around the use of numerical methods, specifically Simpson's Rule and the Trapezium Rule, for calculating the area under a curve. Participants are exploring the contexts in which these methods are preferable compared to traditional integration techniques.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants question the necessity of using numerical methods when analytical integration is possible. They discuss the types of functions that may not be integrable analytically and provide examples of such functions.

Discussion Status

The conversation is ongoing, with participants sharing insights about the limitations of analytical integration and the scenarios where numerical methods become essential. There is an exploration of different perspectives on the effectiveness of these methods.

Contextual Notes

Some participants note that many functions encountered in early studies can be integrated analytically, while others highlight that more complex functions may require numerical approximation methods.

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Why should I use the simpson or trapezium rule when calculating the area under a curve? It is much easier and accurate when using integration the ordinary way :confused:
 
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In general, you must approximate something that is either difficult or impossible to do analytically. Not many functions can be "integrated the ordinary way." Most functions can be approximated, though.

--J
 
Can you give me an example of a function that is impossible to integrate analytiacally?
 
[tex]\mbox{Si}(z) \equiv \int_0^z \frac{\sin{t}}{t} dt[/tex]

--J
 
Last edited:
[tex]\int_0^1 e^{x^2}dx[/tex]

"Almost all" integrals cannot be done analytically.
 
However, "almost all" integrals you learn about in your first year can be solved by the "ordinary" way..:wink:
 
Perhaps more tangable to you in the near future: If you are learning Simson's rule now, you will most likely get to arclength very shortly. You will also find then that sometimes evaluating an integral like

[tex]\int_a^b\sqrt{1+{\left(\frac{dy}{dx}\right)}^2}{dx}[/tex]

Can be very difficult if [itex]\frac{dy}{dx}[/itex] is long or confusing.
 
Last edited:

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