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irony of truth
Mar2-05, 11:19 AM
How do I integrate this? e^[1 / (1 + t)] dt?

arildno
Mar2-05, 11:22 AM
Short answer: Numerically.
There exist no nice anti-derivative to this function.

irony of truth
Mar2-05, 11:24 AM
I see... so this could be the same case as that of (sinx / x) dx...

dextercioby
Mar2-05, 11:25 AM
Long answer:
\allowbreak \left( 1+x\right) e^{\frac 1{1+x}}+\func{Ei}\left( 1,-\frac 1{1+x}\right) +C

Daniel.

dextercioby
Mar2-05, 11:26 AM
I see... so this could be the same case as that of (sinx / x) dx...

Yes,there is a connection between Ei (exp.integral) and Si (sinus integral).

Daniel.

P.S.Chack the wolfram site for more.

arildno
Mar2-05, 11:30 AM
Long answer:
\allowbreak \left( 1+x\right) e^{\frac 1{1+x}}+\func{Ei}\left( 1,-\frac 1{1+x}\right) +C

Daniel.
I'd rather say apparently short answer..

dextercioby
Mar2-05, 11:33 AM
Yes,"apparently" is a well placed word...:wink:

Daniel.

P.S.Anyways,the # of characters from the code is much bigger than the # of letters from "numerically"...