Chem Question: Isoelectronic Ions and Ca Notation Explained

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Homework Help Overview

The discussion revolves around the concept of isoelectronic ions and the notation used for electron configurations, specifically focusing on calcium (Ca) and its relation to argon (Ar). Participants are exploring how to determine if a group of ions is isoelectronic and the meaning of the shorthand notation for electron configurations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the criteria for determining isoelectronic status based on atomic numbers and net charges. There are questions about the shorthand notation for electron configurations and its acceptance in academic settings.

Discussion Status

Some participants have provided explanations regarding the calculation of electron counts for isoelectronic species and the meaning of the shorthand notation. There seems to be a divergence in opinions about the acceptance of shorthand notation in educational contexts, with some expressing concerns about potential grading implications.

Contextual Notes

There is mention of differing expectations among educators regarding shorthand notation in exams, indicating a potential source of confusion for students. The discussion also highlights the importance of clarity in communication of electron configurations.

courtrigrad
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How do you know whether a group of ions is isoelectronic? Also what does this notation mean:

[tex]Ca: [Ar]4s^{2}[/tex]?

Thanks
 
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courtrigrad said:
How do you know whether a group of ions is isoelectronic? Also what does this notation mean:

[tex]Ca: [Ar]4s^{2}[/tex]?

Thanks
An atom or ion is isoelectonic with another atom or ion if the two contain equal numbers of electrons. This can easily be determined from the Atomic Numbers of the 2 species under consideration:
{Number of Electrons} = {Atomic Number} - {Net Charge}

Thus, for a neutral atom, the number of electrons equals the Atomic Number. For example, the neutral atom Ar with Atomic Number (18) has 18 electrons. For the negative ion Cl-1 with charge (-1) and Atomic Number (17), the number of electrons is {(17) - (-1)}=(18). For the positive ion Ca+2 with charge (+2) and Atomic Number (20), the number of electrons equals {(20) - (+2)}=(18).

The terminology:
[tex]Ca: [Ar]4s^{2}[/tex]
indicates that the neutral Ca atom has the same electron energy/orbital structure as neutral Ar PLUS 2 ADDITIONAL ELECTRONS in the "s" Sublevel of the 4th Energy Level (Principle Quantum Number = 4). From this indication, it can be determined that if Ca loses its 2 valence electrons (i.e., the 2 4s2 electrons), the resulting Ca+2 ion will be isoelectronic with the neutral Ar atom.


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Last edited:
xanthym said:
The terminology:
[tex]Ca: [Ar]4s^{2}[/tex]
indicates that the neutral Ca atom has the same electron energy/orbital structure as neutral Ar PLUS 2 ADDITIONAL ELECTRONS in the "s" Sublevel of the 4th Energy Level (Principle Quantum Number = 4).
This has been said but not written so simply for clarity:

[tex]Ca: 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}[/tex] means the same as [tex]Ca: [Ar]4s^{2}[/tex]

It is just a short hand and easier to write but use the long hand in exams or you lose marks. :smile:

The Bob (2004 ©)
 
Nope.It would be ridiculous,if one of the teachers would not accept the shorthanded notation...
But i know that there are a lotta dumb profs out there...

Daniel.
 
dextercioby said:
Nope.It would be ridiculous,if one of the teachers would not accept the shorthanded notation...
But i know that there are a lotta dumb profs out there...

Daniel.
Personally I do not understand why I cannot short hand but there is no mark for it in the mark scheme so it is better to be safe than sorry. :smile:

The Bob (2004 ©)
 

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