Find acceleration of car attached to spring scale

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SUMMARY

The acceleration of a 20.8 kg mass attached to a spring scale on a smooth horizontal surface is determined to be 1.86 m/s² when the spring scale reads a tension force of 38.7 N. This calculation utilizes Newton's Second Law, expressed as F=ma, where the net force is the tension measured by the spring scale. The spring scale indicates zero force when the car is at rest, confirming that the only force acting on the car during motion is the tension force, leading to the established acceleration.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Basic knowledge of tension forces
  • Familiarity with mass and acceleration concepts
  • Ability to perform algebraic calculations
NEXT STEPS
  • Explore advanced applications of Newton's Laws in dynamics
  • Study the effects of friction on acceleration in real-world scenarios
  • Learn about the principles of spring scales and their calibration
  • Investigate the relationship between mass, force, and acceleration in different contexts
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of motion and force dynamics, particularly in relation to spring scales and Newton's Laws.

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A 20.8 kg mass attached to a spring scale rests
on a smooth, horizontal surface. The spring
scale, attached to the front end of a boxcar,
reads T = 38.7 N when the car is in motion. If the spring scale reads zero when the car is at rest, determine the acceleration of the
car, when it is in motion.
 
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Use Newton's 2nd law?
 


To find the acceleration of the car, we can use Newton's Second Law, which states that the net force on an object is equal to its mass multiplied by its acceleration (F=ma). In this scenario, the net force is the tension force (T) measured by the spring scale.

We know that the mass of the car is 20.8 kg and the tension force measured by the spring scale is 38.7 N. Therefore, we can set up the equation as follows:

F=ma
38.7 N = (20.8 kg) a

Solving for a, we get the acceleration of the car to be 1.86 m/s^2.

This means that for every second the car is in motion, its velocity will increase by 1.86 m/s.

It is also important to note that the fact that the spring scale reads zero when the car is at rest tells us that there is no external force acting on the car. This means that the only force acting on the car is the tension force from the spring scale, which is causing the car to accelerate.

In conclusion, the acceleration of the car attached to the spring scale is 1.86 m/s^2.
 

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