Understanding Gauss's Law and Electric Field Distributions

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Homework Help Overview

The discussion revolves around Gauss's Law and electric field distributions, focusing on multiple-choice questions related to spherical conductors, charge distributions, and the effects of additional charges on electric fields.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the correctness of answers to multiple-choice questions regarding electric fields and charge distributions. There are attempts to clarify the implications of Gauss's Law and the symmetry of charge distributions.

Discussion Status

Some participants are revising their answers based on feedback, indicating an ongoing exploration of the concepts. There is a mix of agreement and differing interpretations regarding the application of Gauss's Law to various charge distributions.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the depth of discussion and exploration of concepts. There is an emphasis on understanding the reasoning behind the choices made in the multiple-choice questions.

PhysicsNewb
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Hi, I had three problems to do that are multiple choice, here they are and my answer with them. Please tell me if some are wrong.

1. Spherical conductor of radius R carries char +Q, which statement(s) are correct?

I. Electric field outside the surface of the conductor is the same as the field outside a uniformly charged nonconducting sphere of same radius and charge

II. Electric field inside the surface of the conductor is the same as the field inside a uniformly charged nonconducting sphere of same radius and charge

III. Nonspherical Gaussian surface drawn within the conductor will have a ney electric flux through it

I said that only statement I. was correct.


2. Gauss's law could easily be used to solve for the electric field outside all of the following charge distributions except

A.) charged nonconducting sphere
B.) long straight line of charge
C.) long charged conducting cylinder
D.) charged nonconducting cube
E.) charged nonconducting plane

I chose B. was correct.

3. Uniformly charged nonconducting sphere of radius R, charge +Q, is centered at the origin of a cartesian plane. Field strength at Point P with coordinates (R,0) just outside the surface will double if:

I. Add a point charge +Q at the origin
II. Add a point charge -Q at point (2R, 0)
III. Add a uniformly charged nonconducting sphere with charge -Q and radius 1/2R with its center at the point (2R, O)

I chose I. only as the answer.

Are these right? If not, please help..
 
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PhysicsNewb said:
1. Spherical conductor of radius R carries char +Q, which statement(s) are correct?

I. Electric field outside the surface of the conductor is the same as the field outside a uniformly charged nonconducting sphere of same radius and charge

II. Electric field inside the surface of the conductor is the same as the field inside a uniformly charged nonconducting sphere of same radius and charge

III. Nonspherical Gaussian surface drawn within the conductor will have a ney electric flux through it

I said that only statement I. was correct.
Right.

2. Gauss's law could easily be used to solve for the electric field outside all of the following charge distributions except

A.) charged nonconducting sphere
B.) long straight line of charge
C.) long charged conducting cylinder
D.) charged nonconducting cube
E.) charged nonconducting plane

I chose B. was correct.
Incorrect. Hint: Which charge distribution lacks a simple symmetry?

3. Uniformly charged nonconducting sphere of radius R, charge +Q, is centered at the origin of a cartesian plane. Field strength at Point P with coordinates (R,0) just outside the surface will double if:

I. Add a point charge +Q at the origin
II. Add a point charge -Q at point (2R, 0)
III. Add a uniformly charged nonconducting sphere with charge -Q and radius 1/2R with its center at the point (2R, O)

I chose I. only as the answer.
Incorrect. Add the contributions from each charge to find the new field at point P.
 
I'm going to revise my answers to make number 2. answer D and number 3 answer's I. and II. I think i worked it right this time.
 
Last edited:
PhysicsNewb said:
I'm going to revise my answers to make number 2. answer D and number 3 answer's I. and II.
For question 3, what's the difference between answers II and III (as far as the field at point P is concerned)?
 

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