Projectiles

[carltonblues]

1)A ball is thrown upward with an initial velocity of v = 20 m/s. How long is the ball in the air? What is the greatest height of the ball? When is the ball 15 m
above the ground?


1) I have figured out

t total = 4.08s
greatest height = 20.4m

For the last bit (Finding the time when x=15m), I am having trouble. I know the answer but cannot work it through.

Do I use s = ut+1/2at^2 for it?

If I do, it wont work out because the 20.4 m has to come into it, doesnt it?

Please help!

[dextercioby]

The equation giving height (let's label it through 'y') as function of time is
y(t)=v_{0}t-\frac{1}{2}gt^{2}

Now set "y" to 15m and solve for "t"...

Daniel.

[carltonblues]

The equation giving height (let's label it through 'y') as function of time is
y(t)=v_{0}t-\frac{1}{2}gt^{2}

Now set "y" to 15m and solve for "t"...

Daniel.Cheers mate

[Am kuls]

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