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Gughanath
Mar16-05, 01:56 PM
A ring of mass 0.3kg is threaded on a fixed, rough, horizontal curtain pole. A light inextensible string is attached to the ring. The string and the pole lie in the same vertical plane. The ring is pulled downwards by the string which makes an angle "A" to the horizontal, where tan A=3/4. The tension in the string is 2.5N. The ring is in equilibrium.

This question doesnt seem that difficult, but in which direction does the normal contact force act?

Doc Al
Mar16-05, 03:34 PM
The contact force between the ring and the rod has two components: the component parallel to the rod, which is the friction; the component perpendicular to the rod, which is the normal force. If I picture the setup correctly, the normal force on the ring points up.