What is the Magnitude of Attractive Force Between a Satellite and Earth?

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SUMMARY

The magnitude of the attractive force between a satellite and Earth can be calculated using the formula F = GM(sat)M(Earth)/R². In this case, a 1500 kg satellite orbits Earth with a period of 86400 seconds and a radius of 42200000 meters. The correct mass of Earth is 6.0 x 1024 kg, not 6.0 x 107 kg as initially stated. Additionally, the orbital radius must include the Earth's radius to accurately determine the gravitational force.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with gravitational constant (G = 6.67 x 10-11 N*m²/kg²)
  • Knowledge of orbital mechanics and satellite motion
  • Ability to perform calculations involving scientific notation
NEXT STEPS
  • Review the derivation of Newton's Law of Universal Gravitation
  • Learn about the implications of orbital radius in gravitational calculations
  • Study the effects of satellite mass on gravitational force
  • Explore the concept of gravitational potential energy in orbital mechanics
USEFUL FOR

Students in physics, aerospace engineers, and anyone interested in understanding gravitational forces acting on satellites in orbit.

IamatWork
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A 1500 kg satellite is orbiting planet earth. The period is 86400 seconds and the radius is 42200000 meters. To determine the magnitude of attractive force... you use equation F=GM(sat)M(Earth)/R2. I know that the mass of Earth is 6.0*10(exp)7 kg and the gravitational constant is 6.67*10(exp negative 11) N*m2/kg2. My answer comes out to be 3.37 *10(exp)32, which is not one of my options?
 
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did you account for the radius of the Earth in your calculation. The distance you need to use is orbital height above erath + Earth's radius.

Regards,

Nenad
 
The mass of the Earth is not [tex]6*10^{7}kg[/tex]. It is [tex]6*10^{24}[/tex] kg.

and don't use r2, but rather [tex]r^2[/tex], but I think you knew that already or you probably would have put 2r instead
 
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