Bullet fired into block attached to spring

Click For Summary

Homework Help Overview

The problem involves a bullet being fired into a block attached to a spring, with specific parameters given for the bullet's mass, the block's mass, and the spring constant. The scenario raises questions about the initial speed of the bullet based on the compression of the spring.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the kinetic energy of the bullet and block system and the potential energy stored in the spring. Some suggest using conservation of momentum and energy principles to analyze the problem.

Discussion Status

Participants are exploring various approaches to relate the energies involved in the system. Some guidance has been offered regarding the use of energy conservation principles, but there is no explicit consensus on the method to be used.

Contextual Notes

There is some confusion regarding the initial conditions of the problem, particularly about the stated speed of the bullet and its implications for the calculations. The discussion reflects a need for clarity on the assumptions being made.

tsdemers
Messages
3
Reaction score
0
A 11-g bullet traveling at 208 m/s is fired into a 0.422 kg wooden block anchored to a 100N/m spring. If the speed of the bullet is not known but it is observed that the spring is compressed 53.1 cm, what was the speed of the bullet to the nearest m/s?

Can someone help me out on where to get started? It's confusing how the question tells you the speed of the bullet but then says the speed isn't known.
 
Physics news on Phys.org
I would start with the fact that you know the potential energy of the compressed spring, and since no other information is given, you can assume that all the kinetic energy of the bullet and block was used in compressing the spring. Can you get started from here ?
 
you have to use BOTH conservation of momentum and energy

along came a bullet of some momentum. I'm sure the bullet embeds itself into the block. SO after the bullet struck the block, they both have some common velocity. ow for the energy part.
The velocity has some associated kinetic energy, which was all converted into the spring's energy. Form the relations based on this
 
Just feeling like solving it, the answer is 435.9m/s. Justdo what the guyes befoure me told you to do. All you need is:
[tex]PE_{spring} = \frac{1}{2}kx^2[/tex]
[tex]KE_{system} = \frac{1}{2} (m_{bullet} + m_{block})v_{system}^2[/tex]
Very simple.

Regards,

Nenad
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
14
Views
4K
Replies
17
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K