How Do You Integrate a Wave Function to Find Electron Probability?

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SUMMARY

The discussion centers on integrating the wave function of an electron, specifically ψ2(x) = sqrt(2/L) sin(2πx/L), to calculate the probability of finding the electron between x = 0 and x = L/6. Participants emphasize the importance of computing the probability density |ψ2(x)|² = (2/L)sin²(2πx/L) before performing the integration. The half-angle identity for sine is also highlighted as a useful tool for simplifying the integration process.

PREREQUISITES
  • Understanding of quantum mechanics, specifically wave functions
  • Familiarity with integral calculus
  • Knowledge of probability density functions
  • Proficiency in using trigonometric identities, particularly the half-angle identity
NEXT STEPS
  • Learn how to compute integrals of trigonometric functions in quantum mechanics
  • Study the application of probability density in quantum systems
  • Explore the implications of the one-dimensional infinite square well model
  • Review the derivation and application of the half-angle identity in integration
USEFUL FOR

Students and professionals in quantum mechanics, physicists working with wave functions, and anyone interested in the mathematical foundations of electron probability calculations.

bemigh
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Hey. I am pretty confident i have solve this problem. I just solve the integral of the given wave function, with the given limits... However, I am having a difficult time integrating it. The sqrt(2/L) can be brought outside of the integral, but what can i with the sin function?


The wave function of an electron is
ψ2(x) = sqrt(2/L) sin(2πx/L)
Calculate the probability of finding the electron between x = 0 and x = L/6.

Cheers
 
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So what is the problem...?Compute the probability density first,and then integrate the result between the 2 limits specified in the problem...

Daniel.
 
One-dimensional infinite square well I assume. What's wrong?

[tex]\psi_2 (x) = \sqrt{\frac{2}{L}} \sin{\frac{2\pi x}{L}} \Longrightarrow | \psi_2(x) |^2 = \frac{2}{L}\sin^2{\frac{2\pi x}{L}}[/tex]

integrate from [itex]0[/itex] to [itex]\frac{L}{6}[/itex]... If you don't remember the half-angle identity, here it is:

[tex]\sin^2{x} = \frac{1}{2}(1-\cos{2x})[/tex]
 

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